Saturday, January 16, 2010

Jenson Button: Is this Lewis Hamiltons' team?

Button is so keen for equality with Hamilton at McLaren F1 that he frankly asked bosses: Is this Lewis Hamilton team? 2009 World champion Jenson issued the challenge as he visited the squad's stand in Working. The Reply he received was: No, it is Hamilton’s' team and your team.

To shuffle it up, McLaren F1 has reorder their engineering team to make sure Lewis and Jenson Button are given equivalent grade. Because Hamilton split open on to the F1 scene in 2007, the team has constantly faced questions about favouritism and has just as constantly replied that all their drivers are treated the equal.

 

However, Jenson’s question reveals his worry at having a team-mate who has been part of the McLaren family since he was 12.The employment unexpected result sees Phil Prew, Hamilton's engineer for the previous 3 years, being promoted to McLaren's chief race engineer. Hamilton will currently have at his side Andy Latham, who has been with McLaren since 2000, while Button will be overseen by Jakob Andreason, who was Prew's supporter with Hamilton.

 

McLaren team Managing Director Jonathan Neale, told: When Jenson visited our base, one of the questions he asked was, 'Is this Lewis' team?’. The replay was, 'Yes, of course it's Lewis' team, as it was Heikki Kovalainen's team, Fernando Alonso's, Juan Pablo Montoya's and Kimi Raikkonen's. And it will be your team as well.'

 

Is this Lewis's team to the keeping out of any other high-performance driver? Absolutely Not.” At McLaren, we love winning drivers and we desire to go about telling the world that story. Referring to the reasoning at the back the reorder, Neale replied:  We want to construct an engineering team about Button in precisely the same way we did with Lewis back in 2007.

 

We're giving both a new engineering team, with Phil as the overpass between them.


It ensures greater parity between the drivers but it's primarily to ensure there is total transfer in the learning of set-up growth.